What are the solutions to the equation 2t^2+t+9=2 ?

The solutions to the equation 2t^2+t+9=2 are t=-1/4+i(sqrt(55))/4 ,t=-1/4-i(sqrt(55))/4

Find the zeros of 2t^2+t+9=2

The zeros of 2t^2+t+9=2 are t=-1/4+i(sqrt(55))/4 ,t=-1/4-i(sqrt(55))/4

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2 t^{2} + t + 9 = 2

t = - \frac{1}{4} + i \frac{55}{4}, t = - \frac{1}{4} - i \frac{55}{4}

Solution steps

2 t^{2} + t + 9 = 2

Move

2

to the left side

2 t^{2} + t + 7 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 2 \cdot 7}{2 \cdot 2}

Simplify

1^{2} - 4 \cdot 2 \cdot 7 : 55 i

t_{1, 2} = \frac{- 1 \pm 55 i}{2 \cdot 2}

Separate the solutions

t_{1} = \frac{- 1 + 55 i}{2 \cdot 2}, t_{2} = \frac{- 1 - 55 i}{2 \cdot 2}

t = \frac{- 1 + 55 i}{2 \cdot 2} : - \frac{1}{4} + i \frac{55}{4}

t = \frac{- 1 - 55 i}{2 \cdot 2} : - \frac{1}{4} - i \frac{55}{4}

The solutions to the quadratic equation are:

t = - \frac{1}{4} + i \frac{55}{4}, t = - \frac{1}{4} - i \frac{55}{4}

s^{2} + 4 s + 29

A^{2} = 2 x (4 x + 1)

x^{2} + 30 x + c

x^{2} - 8 x = - 2

(x - 150)^{2} + 16

What are the solutions to the equation 2t^2+t+9=2 ?
The solutions to the equation 2t^2+t+9=2 are t=-1/4+i(sqrt(55))/4 ,t=-1/4-i(sqrt(55))/4
Find the zeros of 2t^2+t+9=2
The zeros of 2t^2+t+9=2 are t=-1/4+i(sqrt(55))/4 ,t=-1/4-i(sqrt(55))/4