What are the solutions to the equation solvefor y,x^2+y^2=-4 ?

The solutions to the equation solvefor y,x^2+y^2=-4 are y=sqrt(-4-x^2),y=-sqrt(-4-x^2)

Find the zeros of solvefor y,x^2+y^2=-4

The zeros of solvefor y,x^2+y^2=-4 are y=sqrt(-4-x^2),y=-sqrt(-4-x^2)

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solve for

y, x^{2} + y^{2} = - 4

y = - 4 - x^{2}, y = - - 4 - x^{2}

Solution steps

x^{2} + y^{2} = - 4

Move

x^{2}

to the right side

y^{2} = - 4 - x^{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = - 4 - x^{2}, y = - - 4 - x^{2}

a (x) = (x - 3) (4 x + 1) + 2 (3 - x) (x + 2)

- 12 x^{2} = 720

m^{2} + 12 m = 0

12 t - 4.9 t^{2} + 70 = 0

a^{2} = e^{2}

What are the solutions to the equation solvefor y,x^2+y^2=-4 ?
The solutions to the equation solvefor y,x^2+y^2=-4 are y=sqrt(-4-x^2),y=-sqrt(-4-x^2)
Find the zeros of solvefor y,x^2+y^2=-4
The zeros of solvefor y,x^2+y^2=-4 are y=sqrt(-4-x^2),y=-sqrt(-4-x^2)