What are the solutions to the equation 2a^2-5a-2=-3a^2 ?

The solutions to the equation 2a^2-5a-2=-3a^2 are a=(5+sqrt(65))/(10),a=(5-sqrt(65))/(10)

Find the zeros of 2a^2-5a-2=-3a^2

The zeros of 2a^2-5a-2=-3a^2 are a=(5+sqrt(65))/(10),a=(5-sqrt(65))/(10)

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2 a^{2} - 5 a - 2 = - 3 a^{2}

a = \frac{5 + 65}{10}, a = \frac{5 - 65}{10}

Decimal Notation

a = 1.30622 \dots, a = - 0.30622 \dots

Solution steps

2 a^{2} - 5 a - 2 = - 3 a^{2}

Move

3 a^{2}

to the left side

5 a^{2} - 5 a - 2 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 5 ( - 2 )}{2 \cdot 5}

(- 5)^{2} - 4 \cdot 5 (- 2) = 65

a_{1, 2} = \frac{- ( - 5 ) \pm 65}{2 \cdot 5}

Separate the solutions

a_{1} = \frac{- ( - 5 ) + 65}{2 \cdot 5}, a_{2} = \frac{- ( - 5 ) - 65}{2 \cdot 5}

a = \frac{- ( - 5 ) + 65}{2 \cdot 5} : \frac{5 + 65}{10}

a = \frac{- ( - 5 ) - 65}{2 \cdot 5} : \frac{5 - 65}{10}

The solutions to the quadratic equation are:

a = \frac{5 + 65}{10}, a = \frac{5 - 65}{10}

m^{2} + 12 = 7 m

3 x^{2} = 6 x + 1

5 x^{2} - 7 x = 2 x - 4

x^{2} - 2 = 1

x, x^{2} + 64 = 0

What are the solutions to the equation 2a^2-5a-2=-3a^2 ?
The solutions to the equation 2a^2-5a-2=-3a^2 are a=(5+sqrt(65))/(10),a=(5-sqrt(65))/(10)
Find the zeros of 2a^2-5a-2=-3a^2
The zeros of 2a^2-5a-2=-3a^2 are a=(5+sqrt(65))/(10),a=(5-sqrt(65))/(10)