What are the solutions to the equation 5x^2-7x=2x-4 ?

The solutions to the equation 5x^2-7x=2x-4 are x=1,x= 4/5

Find the zeros of 5x^2-7x=2x-4

The zeros of 5x^2-7x=2x-4 are x=1,x= 4/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

5 x^{2} - 7 x = 2 x - 4

x = 1, x = \frac{4}{5}

Decimal Notation

x = 1, x = 0.8

Solution steps

5 x^{2} - 7 x = 2 x - 4

Move

4

to the left side

5 x^{2} - 7 x + 4 = 2 x

Move

2 x

to the left side

5 x^{2} - 9 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 5 \cdot 4}{2 \cdot 5}

(- 9)^{2} - 4 \cdot 5 \cdot 4 = 1

x_{1, 2} = \frac{- ( - 9 ) \pm 1}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 1}{2 \cdot 5}, x_{2} = \frac{- ( - 9 ) - 1}{2 \cdot 5}

x = \frac{- ( - 9 ) + 1}{2 \cdot 5} : 1

x = \frac{- ( - 9 ) - 1}{2 \cdot 5} : \frac{4}{5}

The solutions to the quadratic equation are:

x = 1, x = \frac{4}{5}

x^{2} - 2 = 1

x, x^{2} + 64 = 0

8 x^{2} - 8 = 0

- x^{2} + 280 x - 17600

2 t^{2} + 4 t - 6 = 0

What are the solutions to the equation 5x^2-7x=2x-4 ?
The solutions to the equation 5x^2-7x=2x-4 are x=1,x= 4/5
Find the zeros of 5x^2-7x=2x-4
The zeros of 5x^2-7x=2x-4 are x=1,x= 4/5