What are the solutions to the equation -6x^2+9x-7=0 ?

The solutions to the equation -6x^2+9x-7=0 are x= 3/4-i(sqrt(87))/(12),x= 3/4+i(sqrt(87))/(12)

Find the zeros of -6x^2+9x-7=0

The zeros of -6x^2+9x-7=0 are x= 3/4-i(sqrt(87))/(12),x= 3/4+i(sqrt(87))/(12)

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- 6 x^{2} + 9 x - 7 = 0

x = \frac{3}{4} - i \frac{87}{12}, x = \frac{3}{4} + i \frac{87}{12}

Solution steps

- 6 x^{2} + 9 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 ( - 6 ) ( - 7 )}{2 ( - 6 )}

Simplify

9^{2} - 4 (- 6) (- 7) : 87 i

x_{1, 2} = \frac{- 9 \pm 87 i}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- 9 + 87 i}{2 ( - 6 )}, x_{2} = \frac{- 9 - 87 i}{2 ( - 6 )}

x = \frac{- 9 + 87 i}{2 ( - 6 )} : \frac{3}{4} - i \frac{87}{12}

x = \frac{- 9 - 87 i}{2 ( - 6 )} : \frac{3}{4} + i \frac{87}{12}

The solutions to the quadratic equation are:

x = \frac{3}{4} - i \frac{87}{12}, x = \frac{3}{4} + i \frac{87}{12}

2 x^{2} + 9 x - 56 = 0

3 = x^{2} - 4 x + 7

4 d^{2} - d - 7 = 2 d^{2}

- 4 x^{2} - 8 x + 1 = 0

x, x^{2} - 6 x - 3 = 0

What are the solutions to the equation -6x^2+9x-7=0 ?
The solutions to the equation -6x^2+9x-7=0 are x= 3/4-i(sqrt(87))/(12),x= 3/4+i(sqrt(87))/(12)
Find the zeros of -6x^2+9x-7=0
The zeros of -6x^2+9x-7=0 are x= 3/4-i(sqrt(87))/(12),x= 3/4+i(sqrt(87))/(12)