What are the solutions to the equation factor 16x^2+2x-3=0 ?

The solutions to the equation factor 16x^2+2x-3=0 are x= 3/8 ,x=-1/2

Find the zeros of factor 16x^2+2x-3=0

The zeros of factor 16x^2+2x-3=0 are x= 3/8 ,x=-1/2

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16 x^{2} + 2 x - 3 = 0

x = \frac{3}{8}, x = - \frac{1}{2}

Decimal Notation

x = 0.375, x = - 0.5

Solution steps

16 x^{2} + 2 x - 3 = 0

Factor

16 x^{2} + 2 x - 3 : (8 x - 3) (2 x + 1)

(8 x - 3) (2 x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

8 x - 3 = 0 or 2 x + 1 = 0

Solve

8 x - 3 = 0 : x = \frac{3}{8}

Solve

2 x + 1 = 0 : x = - \frac{1}{2}

The solutions to the quadratic equation are:

x = \frac{3}{8}, x = - \frac{1}{2}

x^{2} + x = 272

2 x^{2} + 34 x - 336 = 0

m^{2} - m = 1

0 = x^{2} - \frac{3}{2} x - \frac{70}{8}

x, x^{2} y + 3 y^{3} = 24

What are the solutions to the equation factor 16x^2+2x-3=0 ?
The solutions to the equation factor 16x^2+2x-3=0 are x= 3/8 ,x=-1/2
Find the zeros of factor 16x^2+2x-3=0
The zeros of factor 16x^2+2x-3=0 are x= 3/8 ,x=-1/2