What are the solutions to the equation 8^2=x^2+7^2 ?

The solutions to the equation 8^2=x^2+7^2 are x=sqrt(15),x=-sqrt(15)

Find the zeros of 8^2=x^2+7^2

The zeros of 8^2=x^2+7^2 are x=sqrt(15),x=-sqrt(15)

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8^{2} = x^{2} + 7^{2}

x = 15, x = - 15

Decimal Notation

x = 3.87298 \dots, x = - 3.87298 \dots

Solution steps

8^{2} = x^{2} + 7^{2}

Switch sides

x^{2} + 7^{2} = 8^{2}

Move

7^{2}

to the right side

x^{2} = 15

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 15, x = - 15

w^{2} - 22 w + 121 = 81

x^{2} - 7 = 6

2 (2 x - 4)^{2} - 41 = 29

r^{2} - 6 r + 18 = 0

x^{2} + 26 = - 12 x

What are the solutions to the equation 8^2=x^2+7^2 ?
The solutions to the equation 8^2=x^2+7^2 are x=sqrt(15),x=-sqrt(15)
Find the zeros of 8^2=x^2+7^2
The zeros of 8^2=x^2+7^2 are x=sqrt(15),x=-sqrt(15)