What are the solutions to the equation 1+3x^2=0 ?

The solutions to the equation 1+3x^2=0 are x= 1/(sqrt(3))i,x=-1/(sqrt(3))i

Find the zeros of 1+3x^2=0

The zeros of 1+3x^2=0 are x= 1/(sqrt(3))i,x=-1/(sqrt(3))i

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1 + 3 x^{2} = 0

x = \frac{1}{3} i, x = - \frac{1}{3} i

Solution steps

1 + 3 x^{2} = 0

Move

1

to the right side

3 x^{2} = - 1

Divide both sides by

3

x^{2} = - \frac{1}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{1}{3}, x = - - \frac{1}{3}

- \frac{1}{3} = \frac{1}{3} i

- - \frac{1}{3} = - \frac{1}{3} i

x = \frac{1}{3} i, x = - \frac{1}{3} i

15 x^{2} - 65 x = 0

49 - 14 x - 2 x^{2} = 0

2 d^{2} - 4 d - 5 = 0

3 q^{2} + q - 11 = - 4

(x + 24) \times (x + 2) = 420

What are the solutions to the equation 1+3x^2=0 ?
The solutions to the equation 1+3x^2=0 are x= 1/(sqrt(3))i,x=-1/(sqrt(3))i
Find the zeros of 1+3x^2=0
The zeros of 1+3x^2=0 are x= 1/(sqrt(3))i,x=-1/(sqrt(3))i