What are the solutions to the equation roots x^2+2sqrt(2)x+2 ?

The solutions to the equation roots x^2+2sqrt(2)x+2 are x=-sqrt(2)

Find the zeros of roots x^2+2sqrt(2)x+2

The zeros of roots x^2+2sqrt(2)x+2 are x=-sqrt(2)

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roots

x^{2} + 22 x + 2

x = - 2

Solution steps

x^{2} + 22 x + 2

The roots are the intercepts with the x-axis

(y = 0)

x^{2} + 22 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 2 \pm ( 2 2 ) ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

(22)^{2} - 4 \cdot 1 \cdot 2 = 0

x_{1, 2} = \frac{- 2 2 \pm 0}{2 \cdot 1}

x = \frac{- 2 2}{2 \cdot 1}

\frac{- 2 2}{2 \cdot 1} = - 2

x = - 2

The solution to the quadratic equation is:

x = - 2

2 (x^{2} + 1) - 5 x = 3 (x + 4)

4 x^{2} - 2 x = 5

w^{2} - 14 w + 2 = - 4 w

7 x^{2} + 8 x + 3 = 0

3 x^{2} - 9 x - 84 = 0

What are the solutions to the equation roots x^2+2sqrt(2)x+2 ?
The solutions to the equation roots x^2+2sqrt(2)x+2 are x=-sqrt(2)
Find the zeros of roots x^2+2sqrt(2)x+2
The zeros of roots x^2+2sqrt(2)x+2 are x=-sqrt(2)