What are the solutions to the equation -2x^2-2x=0 ?

The solutions to the equation -2x^2-2x=0 are x=-1,x=0

Find the zeros of -2x^2-2x=0

The zeros of -2x^2-2x=0 are x=-1,x=0

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- 2 x^{2} - 2 x = 0

x = - 1, x = 0

Solution steps

- 2 x^{2} - 2 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 2 ) \cdot 0}{2 ( - 2 )}

(- 2)^{2} - 4 (- 2) \cdot 0 = 2

x_{1, 2} = \frac{- ( - 2 ) \pm 2}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2}{2 ( - 2 )}, x_{2} = \frac{- ( - 2 ) - 2}{2 ( - 2 )}

x = \frac{- ( - 2 ) + 2}{2 ( - 2 )} : - 1

x = \frac{- ( - 2 ) - 2}{2 ( - 2 )} : 0

The solutions to the quadratic equation are:

x = - 1, x = 0

(x - 4)^{2} = 180

x^{2} - 3 x - 4

2 - (x^{2} - 3 x + 8) = (2 x - 3) (1 - x)

x, xx z - 250047 = 0

- (y + 2) (y - 1) = 3

What are the solutions to the equation -2x^2-2x=0 ?
The solutions to the equation -2x^2-2x=0 are x=-1,x=0
Find the zeros of -2x^2-2x=0
The zeros of -2x^2-2x=0 are x=-1,x=0