What are the solutions to the equation solvefor y,4x^2-9y^2-16x-18y+7=0 ?

The solutions to the equation solvefor y,4x^2-9y^2-16x-18y+7=0 are y=-(2x-1)/3 ,y=-(-2x+7)/3

Find the zeros of solvefor y,4x^2-9y^2-16x-18y+7=0

The zeros of solvefor y,4x^2-9y^2-16x-18y+7=0 are y=-(2x-1)/3 ,y=-(-2x+7)/3

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solve for

y, 4 x^{2} - 9 y^{2} - 16 x - 18 y + 7 = 0

y = - \frac{2 x - 1}{3}, y = - \frac{- 2 x + 7}{3}

Solution steps

4 x^{2} - 9 y^{2} - 16 x - 18 y + 7 = 0

Write in the standard form

a x^{2} + b x + c = 0

- 9 y^{2} - 18 y + 4 x^{2} - 16 x + 7 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 ( - 9 ) ( 4 x ^{2} - 16 x + 7 )}{2 ( - 9 )}

Simplify

(- 18)^{2} - 4 (- 9) (4 x^{2} - 16 x + 7) : 12 (x - 2)

y_{1, 2} = \frac{- ( - 18 ) \pm 12 ( x - 2 )}{2 ( - 9 )}

Separate the solutions

y_{1} = \frac{- ( - 18 ) + 12 ( x - 2 )}{2 ( - 9 )}, y_{2} = \frac{- ( - 18 ) - 12 ( x - 2 )}{2 ( - 9 )}

y = \frac{- ( - 18 ) + 12 ( x - 2 )}{2 ( - 9 )} : - \frac{2 x - 1}{3}

y = \frac{- ( - 18 ) - 12 ( x - 2 )}{2 ( - 9 )} : - \frac{- 2 x + 7}{3}

The solutions to the quadratic equation are:

y = - \frac{2 x - 1}{3}, y = - \frac{- 2 x + 7}{3}

x^{2} - 5 x - 10

a^{2} = 196

6 x^{2} - 13 x - 8 = 0

4 x^{2} - 4 x - 3 = 2

x^{2} - 1 = - 4 x

What are the solutions to the equation solvefor y,4x^2-9y^2-16x-18y+7=0 ?
The solutions to the equation solvefor y,4x^2-9y^2-16x-18y+7=0 are y=-(2x-1)/3 ,y=-(-2x+7)/3
Find the zeros of solvefor y,4x^2-9y^2-16x-18y+7=0
The zeros of solvefor y,4x^2-9y^2-16x-18y+7=0 are y=-(2x-1)/3 ,y=-(-2x+7)/3