What are the solutions to the equation x^2+4=-5x ?

The solutions to the equation x^2+4=-5x are x=-1,x=-4

Find the zeros of x^2+4=-5x

The zeros of x^2+4=-5x are x=-1,x=-4

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x^{2} + 4 = - 5 x

x = - 1, x = - 4

Solution steps

x^{2} + 4 = - 5 x

Move

5 x

to the left side

x^{2} + 4 + 5 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} + 5 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot 4 = 3

x_{1, 2} = \frac{- 5 \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 5 + 3}{2 \cdot 1}, x_{2} = \frac{- 5 - 3}{2 \cdot 1}

x = \frac{- 5 + 3}{2 \cdot 1} : - 1

x = \frac{- 5 - 3}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = - 1, x = - 4

x^{2} - 7 x + 10 = 0

h^{2} - 25894.4 h + 1336336 = 0

0 = 3 x^{2} - 2 x - 6

x^{2} + \frac{2}{4} - x - \frac{3}{6} x = 5

x, s = vx + \frac{1}{2} a x^{2}

What are the solutions to the equation x^2+4=-5x ?
The solutions to the equation x^2+4=-5x are x=-1,x=-4
Find the zeros of x^2+4=-5x
The zeros of x^2+4=-5x are x=-1,x=-4