What are the solutions to the equation 3t^2-16t+28=0 ?

The solutions to the equation 3t^2-16t+28=0 are t= 8/3+i(2sqrt(5))/3 ,t= 8/3-i(2sqrt(5))/3

Find the zeros of 3t^2-16t+28=0

The zeros of 3t^2-16t+28=0 are t= 8/3+i(2sqrt(5))/3 ,t= 8/3-i(2sqrt(5))/3

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3 t^{2} - 16 t + 28 = 0

t = \frac{8}{3} + i \frac{2 5}{3}, t = \frac{8}{3} - i \frac{2 5}{3}

Solution steps

3 t^{2} - 16 t + 28 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 3 \cdot 28}{2 \cdot 3}

Simplify

(- 16)^{2} - 4 \cdot 3 \cdot 28 : 45 i

t_{1, 2} = \frac{- ( - 16 ) \pm 4 5 i}{2 \cdot 3}

Separate the solutions

t_{1} = \frac{- ( - 16 ) + 4 5 i}{2 \cdot 3}, t_{2} = \frac{- ( - 16 ) - 4 5 i}{2 \cdot 3}

t = \frac{- ( - 16 ) + 4 5 i}{2 \cdot 3} : \frac{8}{3} + i \frac{2 5}{3}

t = \frac{- ( - 16 ) - 4 5 i}{2 \cdot 3} : \frac{8}{3} - i \frac{2 5}{3}

The solutions to the quadratic equation are:

t = \frac{8}{3} + i \frac{2 5}{3}, t = \frac{8}{3} - i \frac{2 5}{3}

x (2 x - 1) = 120

4 z^{2} - 100 = - 80

x^{2} - 5 x + \frac{5}{4}

- \frac{1}{5} x^{2} + 20 = 0

8 x^{2} - 5 x - 3 = 0

What are the solutions to the equation 3t^2-16t+28=0 ?
The solutions to the equation 3t^2-16t+28=0 are t= 8/3+i(2sqrt(5))/3 ,t= 8/3-i(2sqrt(5))/3
Find the zeros of 3t^2-16t+28=0
The zeros of 3t^2-16t+28=0 are t= 8/3+i(2sqrt(5))/3 ,t= 8/3-i(2sqrt(5))/3