What are the solutions to the equation roots 2x^2+2x+1 ?

The solutions to the equation roots 2x^2+2x+1 are x=-1/2+i 1/2 ,x=-1/2-i 1/2

Find the zeros of roots 2x^2+2x+1

The zeros of roots 2x^2+2x+1 are x=-1/2+i 1/2 ,x=-1/2-i 1/2

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roots

2 x^{2} + 2 x + 1

x = - \frac{1}{2} + i \frac{1}{2}, x = - \frac{1}{2} - i \frac{1}{2}

Solution steps

2 x^{2} + 2 x + 1

The roots are the intercepts with the x-axis

(y = 0)

2 x^{2} + 2 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 2 \cdot 1}{2 \cdot 2}

Simplify

2^{2} - 4 \cdot 2 \cdot 1 : 2 i

x_{1, 2} = \frac{- 2 \pm 2 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 2 + 2 i}{2 \cdot 2}, x_{2} = \frac{- 2 - 2 i}{2 \cdot 2}

x = \frac{- 2 + 2 i}{2 \cdot 2} : - \frac{1}{2} + i \frac{1}{2}

x = \frac{- 2 - 2 i}{2 \cdot 2} : - \frac{1}{2} - i \frac{1}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2} + i \frac{1}{2}, x = - \frac{1}{2} - i \frac{1}{2}

x^{2} + (x - 1)^{2} = 1

(x + 20)^{2} = 625

x^{2} - (2 x + 1)^{2} = - 21

0 = - 0.04 x^{2} + 0.8 x + 9

4 x^{2} - 15 x + 14 = 0

What are the solutions to the equation roots 2x^2+2x+1 ?
The solutions to the equation roots 2x^2+2x+1 are x=-1/2+i 1/2 ,x=-1/2-i 1/2
Find the zeros of roots 2x^2+2x+1
The zeros of roots 2x^2+2x+1 are x=-1/2+i 1/2 ,x=-1/2-i 1/2