What are the solutions to the equation 47y^2=-15y ?

The solutions to the equation 47y^2=-15y are y=0,y=-15/47

Find the zeros of 47y^2=-15y

The zeros of 47y^2=-15y are y=0,y=-15/47

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47 y^{2} = - 15 y

y = 0, y = - \frac{15}{47}

Decimal Notation

y = 0, y = - 0.31914 \dots

Solution steps

47 y^{2} = - 15 y

Move

15 y

to the left side

47 y^{2} + 15 y = 0

Factor

47 y^{2} + 15 y : y (47 y + 15)

y (47 y + 15) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

y = 0 or 47 y + 15 = 0

Solve

47 y + 15 = 0 : y = - \frac{15}{47}

The solutions to the quadratic equation are:

y = 0, y = - \frac{15}{47}

x^{2} - 10 x + 45 = 0

x^{2} + 8 x = - 7

0 = 12 x^{2} - 28 x + 12

(4 - x) (1 - x) + 2 = 0

2 z^{2} + 2.5 z + 3.75 = 0

What are the solutions to the equation 47y^2=-15y ?
The solutions to the equation 47y^2=-15y are y=0,y=-15/47
Find the zeros of 47y^2=-15y
The zeros of 47y^2=-15y are y=0,y=-15/47