What are the solutions to the equation -0.1x^2+0.8x+8=0 ?

The solutions to the equation -0.1x^2+0.8x+8=0 are x=-4(sqrt(6)-1),x=4(1+sqrt(6))

Find the zeros of -0.1x^2+0.8x+8=0

The zeros of -0.1x^2+0.8x+8=0 are x=-4(sqrt(6)-1),x=4(1+sqrt(6))

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- 0.1 x^{2} + 0.8 x + 8 = 0

x = - 4 (6 - 1), x = 4 (1 + 6)

Decimal Notation

x = - 5.79795 \dots, x = 13.79795 \dots

Solution steps

- 0.1 x^{2} + 0.8 x + 8 = 0

Multiply both sides by

10

- x^{2} + 8 x + 80 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 1 ) \cdot 80}{2 ( - 1 )}

8^{2} - 4 (- 1) \cdot 80 = 86

x_{1, 2} = \frac{- 8 \pm 8 6}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 8 + 8 6}{2 ( - 1 )}, x_{2} = \frac{- 8 - 8 6}{2 ( - 1 )}

x = \frac{- 8 + 8 6}{2 ( - 1 )} : - 4 (6 - 1)

x = \frac{- 8 - 8 6}{2 ( - 1 )} : 4 (1 + 6)

The solutions to the quadratic equation are:

x = - 4 (6 - 1), x = 4 (1 + 6)

- 4 x^{3} y (- 15 x y^{5})

\frac{5}{3} + 2

4 \leq \frac{2}{3} x + 2 < 10

\frac{5}{6} x + \frac{7}{9} - \frac{2}{3} x = \frac{2}{9} x - \frac{5}{9}

v^{2} = 144

What are the solutions to the equation -0.1x^2+0.8x+8=0 ?
The solutions to the equation -0.1x^2+0.8x+8=0 are x=-4(sqrt(6)-1),x=4(1+sqrt(6))
Find the zeros of -0.1x^2+0.8x+8=0
The zeros of -0.1x^2+0.8x+8=0 are x=-4(sqrt(6)-1),x=4(1+sqrt(6))