What are the solutions to the equation 10x^2-6x-3=0 ?

The solutions to the equation 10x^2-6x-3=0 are x=(3+sqrt(39))/(10),x=(3-sqrt(39))/(10)

Find the zeros of 10x^2-6x-3=0

The zeros of 10x^2-6x-3=0 are x=(3+sqrt(39))/(10),x=(3-sqrt(39))/(10)

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10 x^{2} - 6 x - 3 = 0

x = \frac{3 + 39}{10}, x = \frac{3 - 39}{10}

Decimal Notation

x = 0.92449 \dots, x = - 0.32449 \dots

Solution steps

10 x^{2} - 6 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 10 ( - 3 )}{2 \cdot 10}

(- 6)^{2} - 4 \cdot 10 (- 3) = 239

x_{1, 2} = \frac{- ( - 6 ) \pm 2 39}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 39}{2 \cdot 10}, x_{2} = \frac{- ( - 6 ) - 2 39}{2 \cdot 10}

x = \frac{- ( - 6 ) + 2 39}{2 \cdot 10} : \frac{3 + 39}{10}

x = \frac{- ( - 6 ) - 2 39}{2 \cdot 10} : \frac{3 - 39}{10}

The solutions to the quadratic equation are:

x = \frac{3 + 39}{10}, x = \frac{3 - 39}{10}

81 x^{2} + 49 = 0

3 x^{2} - 12 x + 8

3 z^{2} - 5 z - 2 = 0

2 x^{2} - 11 x + 13 = 0

470 = 1.33 x - 0.04 x^{2}

What are the solutions to the equation 10x^2-6x-3=0 ?
The solutions to the equation 10x^2-6x-3=0 are x=(3+sqrt(39))/(10),x=(3-sqrt(39))/(10)
Find the zeros of 10x^2-6x-3=0
The zeros of 10x^2-6x-3=0 are x=(3+sqrt(39))/(10),x=(3-sqrt(39))/(10)