What are the solutions to the equation -4x^2-2x+6=0 ?

The solutions to the equation -4x^2-2x+6=0 are x=-3/2 ,x=1

Find the zeros of -4x^2-2x+6=0

The zeros of -4x^2-2x+6=0 are x=-3/2 ,x=1

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- 4 x^{2} - 2 x + 6 = 0

x = - \frac{3}{2}, x = 1

Decimal Notation

x = - 1.5, x = 1

Solution steps

- 4 x^{2} - 2 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 ( - 4 ) \cdot 6}{2 ( - 4 )}

(- 2)^{2} - 4 (- 4) \cdot 6 = 10

x_{1, 2} = \frac{- ( - 2 ) \pm 10}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 10}{2 ( - 4 )}, x_{2} = \frac{- ( - 2 ) - 10}{2 ( - 4 )}

x = \frac{- ( - 2 ) + 10}{2 ( - 4 )} : - \frac{3}{2}

x = \frac{- ( - 2 ) - 10}{2 ( - 4 )} : 1

The solutions to the quadratic equation are:

x = - \frac{3}{2}, x = 1

0 = - 0.08 x^{2} + 40 x - 1800

25 (x^{2} - 1) + 12 = - 12

- x - 2 = x^{2} + 4 x + 4

2 x^{2} - 12 x + 3

- 20 w = 4 w^{2} + 25

What are the solutions to the equation -4x^2-2x+6=0 ?
The solutions to the equation -4x^2-2x+6=0 are x=-3/2 ,x=1
Find the zeros of -4x^2-2x+6=0
The zeros of -4x^2-2x+6=0 are x=-3/2 ,x=1