What are the solutions to the equation 4x^2-10x+25=0 ?

The solutions to the equation 4x^2-10x+25=0 are x= 5/4+i(5sqrt(3))/4 ,x= 5/4-i(5sqrt(3))/4

Find the zeros of 4x^2-10x+25=0

The zeros of 4x^2-10x+25=0 are x= 5/4+i(5sqrt(3))/4 ,x= 5/4-i(5sqrt(3))/4

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4 x^{2} - 10 x + 25 = 0

x = \frac{5}{4} + i \frac{5 3}{4}, x = \frac{5}{4} - i \frac{5 3}{4}

Solution steps

4 x^{2} - 10 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 4 \cdot 25}{2 \cdot 4}

Simplify

(- 10)^{2} - 4 \cdot 4 \cdot 25 : 103 i

x_{1, 2} = \frac{- ( - 10 ) \pm 10 3 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 10 ) + 10 3 i}{2 \cdot 4}, x_{2} = \frac{- ( - 10 ) - 10 3 i}{2 \cdot 4}

x = \frac{- ( - 10 ) + 10 3 i}{2 \cdot 4} : \frac{5}{4} + i \frac{5 3}{4}

x = \frac{- ( - 10 ) - 10 3 i}{2 \cdot 4} : \frac{5}{4} - i \frac{5 3}{4}

The solutions to the quadratic equation are:

x = \frac{5}{4} + i \frac{5 3}{4}, x = \frac{5}{4} - i \frac{5 3}{4}

x, 6 x^{2} + x - 1 = 0

x^{2} - 9 x = - 22

5 x^{2} - 11 x + 12 = 6

x, x^{2} - y + z^{2} = 0

3 x^{2} + 16 x = 35

What are the solutions to the equation 4x^2-10x+25=0 ?
The solutions to the equation 4x^2-10x+25=0 are x= 5/4+i(5sqrt(3))/4 ,x= 5/4-i(5sqrt(3))/4
Find the zeros of 4x^2-10x+25=0
The zeros of 4x^2-10x+25=0 are x= 5/4+i(5sqrt(3))/4 ,x= 5/4-i(5sqrt(3))/4