What are the solutions to the equation 2y^2-6y+5=0 ?

The solutions to the equation 2y^2-6y+5=0 are y= 3/2+i 1/2 ,y= 3/2-i 1/2

Find the zeros of 2y^2-6y+5=0

The zeros of 2y^2-6y+5=0 are y= 3/2+i 1/2 ,y= 3/2-i 1/2

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2 y^{2} - 6 y + 5 = 0

y = \frac{3}{2} + i \frac{1}{2}, y = \frac{3}{2} - i \frac{1}{2}

Solution steps

2 y^{2} - 6 y + 5 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 2 \cdot 5}{2 \cdot 2}

Simplify

(- 6)^{2} - 4 \cdot 2 \cdot 5 : 2 i

y_{1, 2} = \frac{- ( - 6 ) \pm 2 i}{2 \cdot 2}

Separate the solutions

y_{1} = \frac{- ( - 6 ) + 2 i}{2 \cdot 2}, y_{2} = \frac{- ( - 6 ) - 2 i}{2 \cdot 2}

y = \frac{- ( - 6 ) + 2 i}{2 \cdot 2} : \frac{3}{2} + i \frac{1}{2}

y = \frac{- ( - 6 ) - 2 i}{2 \cdot 2} : \frac{3}{2} - i \frac{1}{2}

The solutions to the quadratic equation are:

y = \frac{3}{2} + i \frac{1}{2}, y = \frac{3}{2} - i \frac{1}{2}

x^{2} - 30 x - 100 = 0

3 \cdot 0.0008 \cdot x^{2} - 4.4 x + 1400 = 0

5 x (x - 1) = 2 (x + 3)

5 = - 16 t^{2} + 22 t + 6

x^{2} - 2 x = 124

What are the solutions to the equation 2y^2-6y+5=0 ?
The solutions to the equation 2y^2-6y+5=0 are y= 3/2+i 1/2 ,y= 3/2-i 1/2
Find the zeros of 2y^2-6y+5=0
The zeros of 2y^2-6y+5=0 are y= 3/2+i 1/2 ,y= 3/2-i 1/2