What are the solutions to the equation x^2-7x=x-13 ?

The solutions to the equation x^2-7x=x-13 are x=4+sqrt(3),x=4-sqrt(3)

Find the zeros of x^2-7x=x-13

The zeros of x^2-7x=x-13 are x=4+sqrt(3),x=4-sqrt(3)

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x^{2} - 7 x = x - 13

x = 4 + 3, x = 4 - 3

Decimal Notation

x = 5.73205 \dots, x = 2.26794 \dots

Solution steps

x^{2} - 7 x = x - 13

Move

13

to the left side

x^{2} - 7 x + 13 = x

Move

x

to the left side

x^{2} - 8 x + 13 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 13}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 13 = 23

x_{1, 2} = \frac{- ( - 8 ) \pm 2 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 2 3}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 2 3}{2 \cdot 1}

x = \frac{- ( - 8 ) + 2 3}{2 \cdot 1} : 4 + 3

x = \frac{- ( - 8 ) - 2 3}{2 \cdot 1} : 4 - 3

The solutions to the quadratic equation are:

x = 4 + 3, x = 4 - 3

4 x^{2} = 4 x + 1

5 x^{2} = - 45 x

0 = - 2 x^{2} + 3 x - 1

3 x^{2} = 12 - 16 x

n^{2} - 10 n - 8 = 0

What are the solutions to the equation x^2-7x=x-13 ?
The solutions to the equation x^2-7x=x-13 are x=4+sqrt(3),x=4-sqrt(3)
Find the zeros of x^2-7x=x-13
The zeros of x^2-7x=x-13 are x=4+sqrt(3),x=4-sqrt(3)