What are the solutions to the equation roots 25x^2+50x+169=0 ?

The solutions to the equation roots 25x^2+50x+169=0 are x=-1+i 12/5 ,x=-1-i 12/5

Find the zeros of roots 25x^2+50x+169=0

The zeros of roots 25x^2+50x+169=0 are x=-1+i 12/5 ,x=-1-i 12/5

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roots

25 x^{2} + 50 x + 169 = 0

x = - 1 + i \frac{12}{5}, x = - 1 - i \frac{12}{5}

Solution steps

25 x^{2} + 50 x + 169 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 50 \pm 5 0 ^{2} - 4 \cdot 25 \cdot 169}{2 \cdot 25}

Simplify

5 0^{2} - 4 \cdot 25 \cdot 169 : 120 i

x_{1, 2} = \frac{- 50 \pm 120 i}{2 \cdot 25}

Separate the solutions

x_{1} = \frac{- 50 + 120 i}{2 \cdot 25}, x_{2} = \frac{- 50 - 120 i}{2 \cdot 25}

x = \frac{- 50 + 120 i}{2 \cdot 25} : - 1 + i \frac{12}{5}

x = \frac{- 50 - 120 i}{2 \cdot 25} : - 1 - i \frac{12}{5}

The solutions to the quadratic equation are:

x = - 1 + i \frac{12}{5}, x = - 1 - i \frac{12}{5}

\frac{1}{4} x^{2} + 2 x + 3 = 0

7 x^{2} + 4 x = 6

3 w^{2} - 75 = 0

y, x^{2} y - x y^{2} + y^{2} = 7

25 t^{2} + 20 t + 3 = - 1

What are the solutions to the equation roots 25x^2+50x+169=0 ?
The solutions to the equation roots 25x^2+50x+169=0 are x=-1+i 12/5 ,x=-1-i 12/5
Find the zeros of roots 25x^2+50x+169=0
The zeros of roots 25x^2+50x+169=0 are x=-1+i 12/5 ,x=-1-i 12/5