What are the solutions to the equation -x^2+6x=10 ?

The solutions to the equation -x^2+6x=10 are x=3-i,x=3+i

Find the zeros of -x^2+6x=10

The zeros of -x^2+6x=10 are x=3-i,x=3+i

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- x^{2} + 6 x = 10

x = 3 - i, x = 3 + i

Solution steps

- x^{2} + 6 x = 10

Move

10

to the left side

- x^{2} + 6 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 ( - 1 ) ( - 10 )}{2 ( - 1 )}

Simplify

6^{2} - 4 (- 1) (- 10) : 2 i

x_{1, 2} = \frac{- 6 \pm 2 i}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 6 + 2 i}{2 ( - 1 )}, x_{2} = \frac{- 6 - 2 i}{2 ( - 1 )}

x = \frac{- 6 + 2 i}{2 ( - 1 )} : 3 - i

x = \frac{- 6 - 2 i}{2 ( - 1 )} : 3 + i

The solutions to the quadratic equation are:

x = 3 - i, x = 3 + i

y, x^{2} - x (y - 2) - 3 y = 0

x^{2} - \frac{11}{10} x + \frac{1}{10} = 0

A, A = 2 π r^{2} + 2 π

4 u^{2} + 20 u = - 25

2 x^{2} - 9 x + 13 = 0

What are the solutions to the equation -x^2+6x=10 ?
The solutions to the equation -x^2+6x=10 are x=3-i,x=3+i
Find the zeros of -x^2+6x=10
The zeros of -x^2+6x=10 are x=3-i,x=3+i