What are the solutions to the equation 4p^2-7p+6=5 ?

The solutions to the equation 4p^2-7p+6=5 are p=(7+sqrt(33))/8 ,p=(7-sqrt(33))/8

Find the zeros of 4p^2-7p+6=5

The zeros of 4p^2-7p+6=5 are p=(7+sqrt(33))/8 ,p=(7-sqrt(33))/8

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4 p^{2} - 7 p + 6 = 5

p = \frac{7 + 33}{8}, p = \frac{7 - 33}{8}

Decimal Notation

p = 1.59307 \dots, p = 0.15692 \dots

Solution steps

4 p^{2} - 7 p + 6 = 5

Move

5

to the left side

4 p^{2} - 7 p + 1 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 4 \cdot 1}{2 \cdot 4}

(- 7)^{2} - 4 \cdot 4 \cdot 1 = 33

p_{1, 2} = \frac{- ( - 7 ) \pm 33}{2 \cdot 4}

Separate the solutions

p_{1} = \frac{- ( - 7 ) + 33}{2 \cdot 4}, p_{2} = \frac{- ( - 7 ) - 33}{2 \cdot 4}

p = \frac{- ( - 7 ) + 33}{2 \cdot 4} : \frac{7 + 33}{8}

p = \frac{- ( - 7 ) - 33}{2 \cdot 4} : \frac{7 - 33}{8}

The solutions to the quadratic equation are:

p = \frac{7 + 33}{8}, p = \frac{7 - 33}{8}

0 = 1 - x - x^{2}

y, 3 x^{2} y + 48 x = 0

75 x^{2} - 60 x = - 12

(2 m - 1) x^{2} + 6 x + 9 = 0

z^{2} + 49 = 0

What are the solutions to the equation 4p^2-7p+6=5 ?
The solutions to the equation 4p^2-7p+6=5 are p=(7+sqrt(33))/8 ,p=(7-sqrt(33))/8
Find the zeros of 4p^2-7p+6=5
The zeros of 4p^2-7p+6=5 are p=(7+sqrt(33))/8 ,p=(7-sqrt(33))/8