What are the solutions to the equation -2x^2+16x=-74 ?

The solutions to the equation -2x^2+16x=-74 are x=4-sqrt(53),x=4+sqrt(53)

Find the zeros of -2x^2+16x=-74

The zeros of -2x^2+16x=-74 are x=4-sqrt(53),x=4+sqrt(53)

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- 2 x^{2} + 16 x = - 74

x = 4 - 53, x = 4 + 53

Decimal Notation

x = - 3.28010 \dots, x = 11.28010 \dots

Solution steps

- 2 x^{2} + 16 x = - 74

Move

74

to the left side

- 2 x^{2} + 16 x + 74 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 ( - 2 ) \cdot 74}{2 ( - 2 )}

1 6^{2} - 4 (- 2) \cdot 74 = 453

x_{1, 2} = \frac{- 16 \pm 4 53}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 16 + 4 53}{2 ( - 2 )}, x_{2} = \frac{- 16 - 4 53}{2 ( - 2 )}

x = \frac{- 16 + 4 53}{2 ( - 2 )} : 4 - 53

x = \frac{- 16 - 4 53}{2 ( - 2 )} : 4 + 53

The solutions to the quadratic equation are:

x = 4 - 53, x = 4 + 53

r^{2} + 4 r + 13

5 x^{2} + 10 x = 0

2 W^{2} - 5 W - 33 = 0

6 x^{2} + 10 x + 25 = 5 x^{2}

v^{2} + v - 12 = 0

What are the solutions to the equation -2x^2+16x=-74 ?
The solutions to the equation -2x^2+16x=-74 are x=4-sqrt(53),x=4+sqrt(53)
Find the zeros of -2x^2+16x=-74
The zeros of -2x^2+16x=-74 are x=4-sqrt(53),x=4+sqrt(53)