What are the solutions to the equation 3x^2-4x+5=4 ?

The solutions to the equation 3x^2-4x+5=4 are x=1,x= 1/3

Find the zeros of 3x^2-4x+5=4

The zeros of 3x^2-4x+5=4 are x=1,x= 1/3

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3 x^{2} - 4 x + 5 = 4

x = 1, x = \frac{1}{3}

Decimal Notation

x = 1, x = 0.33333 \dots

Solution steps

3 x^{2} - 4 x + 5 = 4

Move

4

to the left side

3 x^{2} - 4 x + 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 3 \cdot 1}{2 \cdot 3}

(- 4)^{2} - 4 \cdot 3 \cdot 1 = 2

x_{1, 2} = \frac{- ( - 4 ) \pm 2}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2}{2 \cdot 3}, x_{2} = \frac{- ( - 4 ) - 2}{2 \cdot 3}

x = \frac{- ( - 4 ) + 2}{2 \cdot 3} : 1

x = \frac{- ( - 4 ) - 2}{2 \cdot 3} : \frac{1}{3}

The solutions to the quadratic equation are:

x = 1, x = \frac{1}{3}

2 x^{2} + 5 x - 11 = 1

s^{2} + 14 s + 2

2 x^{2} - 11 x + 14

4 x^{2} - 20 x + 26 = 0

2 x^{2} - x - 1 = 5

What are the solutions to the equation 3x^2-4x+5=4 ?
The solutions to the equation 3x^2-4x+5=4 are x=1,x= 1/3
Find the zeros of 3x^2-4x+5=4
The zeros of 3x^2-4x+5=4 are x=1,x= 1/3