What are the solutions to the equation roots x^2+8x+25=0 ?

The solutions to the equation roots x^2+8x+25=0 are x=-4+3i,x=-4-3i

Find the zeros of roots x^2+8x+25=0

The zeros of roots x^2+8x+25=0 are x=-4+3i,x=-4-3i

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roots

x^{2} + 8 x + 25 = 0

x = - 4 + 3 i, x = - 4 - 3 i

Solution steps

x^{2} + 8 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

Simplify

8^{2} - 4 \cdot 1 \cdot 25 : 6 i

x_{1, 2} = \frac{- 8 \pm 6 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 6 i}{2 \cdot 1}, x_{2} = \frac{- 8 - 6 i}{2 \cdot 1}

x = \frac{- 8 + 6 i}{2 \cdot 1} : - 4 + 3 i

x = \frac{- 8 - 6 i}{2 \cdot 1} : - 4 - 3 i

The solutions to the quadratic equation are:

x = - 4 + 3 i, x = - 4 - 3 i

8 x^{2} + 9 = 313

16 x^{2} - 25 = 0

3 x^{2} + 18 = 15 x

x^{2} - 2 x - 3 = - 4

3 x^{2} - 138 x + 1200 = 0

What are the solutions to the equation roots x^2+8x+25=0 ?
The solutions to the equation roots x^2+8x+25=0 are x=-4+3i,x=-4-3i
Find the zeros of roots x^2+8x+25=0
The zeros of roots x^2+8x+25=0 are x=-4+3i,x=-4-3i