What are the solutions to the equation r^2=-2 ?

The solutions to the equation r^2=-2 are r=sqrt(2)i,r=-sqrt(2)i

Find the zeros of r^2=-2

The zeros of r^2=-2 are r=sqrt(2)i,r=-sqrt(2)i

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r^{2} = - 2

r = 2 i, r = - 2 i

Solution steps

r^{2} = - 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

r = - 2, r = - - 2

- 2 = 2 i

- - 2 = - 2 i

r = 2 i, r = - 2 i

9 (x^{2} - 10) + 14 = - 12

a^{2} + 6 a - 16 = 0

\frac{78 - 3 p ^{2}}{5} = 6

x (x - 1) = 56

x^{2} - 50 x = 0

What are the solutions to the equation r^2=-2 ?
The solutions to the equation r^2=-2 are r=sqrt(2)i,r=-sqrt(2)i
Find the zeros of r^2=-2
The zeros of r^2=-2 are r=sqrt(2)i,r=-sqrt(2)i