What are the solutions to the equation -3x^2+33=48x ?

The solutions to the equation -3x^2+33=48x are x=-8-5sqrt(3),x=5sqrt(3)-8

Find the zeros of -3x^2+33=48x

The zeros of -3x^2+33=48x are x=-8-5sqrt(3),x=5sqrt(3)-8

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- 3 x^{2} + 33 = 48 x

x = - 8 - 53, x = 53 - 8

Decimal Notation

x = - 16.66025 \dots, x = 0.66025 \dots

Solution steps

- 3 x^{2} + 33 = 48 x

Move

48 x

to the left side

- 3 x^{2} + 33 - 48 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- 3 x^{2} - 48 x + 33 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 48 ) \pm ( - 48 ) ^{2} - 4 ( - 3 ) \cdot 33}{2 ( - 3 )}

(- 48)^{2} - 4 (- 3) \cdot 33 = 303

x_{1, 2} = \frac{- ( - 48 ) \pm 30 3}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- ( - 48 ) + 30 3}{2 ( - 3 )}, x_{2} = \frac{- ( - 48 ) - 30 3}{2 ( - 3 )}

x = \frac{- ( - 48 ) + 30 3}{2 ( - 3 )} : - 8 - 53

x = \frac{- ( - 48 ) - 30 3}{2 ( - 3 )} : 53 - 8

The solutions to the quadratic equation are:

x = - 8 - 53, x = 53 - 8

x^{2} + 10 x = 32

4 x^{2} + 5 = - 12 x

x^{2} - 5 x + 10 = 4

s^{2} - 4 s + 3 = 0

3 x^{2} + 24 x + 3 = 0

What are the solutions to the equation -3x^2+33=48x ?
The solutions to the equation -3x^2+33=48x are x=-8-5sqrt(3),x=5sqrt(3)-8
Find the zeros of -3x^2+33=48x
The zeros of -3x^2+33=48x are x=-8-5sqrt(3),x=5sqrt(3)-8