What are the solutions to the equation 4t^2+4t-1=0 ?

The solutions to the equation 4t^2+4t-1=0 are t=(-1+sqrt(2))/2 ,t=-(1+sqrt(2))/2

Find the zeros of 4t^2+4t-1=0

The zeros of 4t^2+4t-1=0 are t=(-1+sqrt(2))/2 ,t=-(1+sqrt(2))/2

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4 t^{2} + 4 t - 1 = 0

t = \frac{- 1 + 2}{2}, t = - \frac{1 + 2}{2}

Decimal Notation

t = 0.20710 \dots, t = - 1.20710 \dots

Solution steps

4 t^{2} + 4 t - 1 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 4 ( - 1 )}{2 \cdot 4}

4^{2} - 4 \cdot 4 (- 1) = 42

t_{1, 2} = \frac{- 4 \pm 4 2}{2 \cdot 4}

Separate the solutions

t_{1} = \frac{- 4 + 4 2}{2 \cdot 4}, t_{2} = \frac{- 4 - 4 2}{2 \cdot 4}

t = \frac{- 4 + 4 2}{2 \cdot 4} : \frac{- 1 + 2}{2}

t = \frac{- 4 - 4 2}{2 \cdot 4} : - \frac{1 + 2}{2}

The solutions to the quadratic equation are:

t = \frac{- 1 + 2}{2}, t = - \frac{1 + 2}{2}

x^{2} - 5 x - 1 = - 1

x + c = x^{2} - x - 12

2 x^{2} + 144 = 0

c, m c^{2} - 2 k = m g

x^{2} + 4 x - 4

What are the solutions to the equation 4t^2+4t-1=0 ?
The solutions to the equation 4t^2+4t-1=0 are t=(-1+sqrt(2))/2 ,t=-(1+sqrt(2))/2
Find the zeros of 4t^2+4t-1=0
The zeros of 4t^2+4t-1=0 are t=(-1+sqrt(2))/2 ,t=-(1+sqrt(2))/2