What are the solutions to the equation x^2+60=16x ?

The solutions to the equation x^2+60=16x are x=10,x=6

Find the zeros of x^2+60=16x

The zeros of x^2+60=16x are x=10,x=6

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x^{2} + 60 = 16 x

x = 10, x = 6

Solution steps

x^{2} + 60 = 16 x

Move

16 x

to the left side

x^{2} + 60 - 16 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 16 x + 60 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot 60}{2 \cdot 1}

(- 16)^{2} - 4 \cdot 1 \cdot 60 = 4

x_{1, 2} = \frac{- ( - 16 ) \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 16 ) + 4}{2 \cdot 1}, x_{2} = \frac{- ( - 16 ) - 4}{2 \cdot 1}

x = \frac{- ( - 16 ) + 4}{2 \cdot 1} : 10

x = \frac{- ( - 16 ) - 4}{2 \cdot 1} : 6

The solutions to the quadratic equation are:

x = 10, x = 6

\frac{x}{3} - 4 = 5

- 4 + - 16

\frac{x ^{2} + 5 x y + 6 y ^{2}}{x + 2 y}

x^{2} - 8 x = 0

5 s^{2} - 20

What are the solutions to the equation x^2+60=16x ?
The solutions to the equation x^2+60=16x are x=10,x=6
Find the zeros of x^2+60=16x
The zeros of x^2+60=16x are x=10,x=6