What are the solutions to the equation x^2-0.5x+0.5=0 ?

The solutions to the equation x^2-0.5x+0.5=0 are x= 1/4+i(sqrt(7))/4 ,x= 1/4-i(sqrt(7))/4

Find the zeros of x^2-0.5x+0.5=0

The zeros of x^2-0.5x+0.5=0 are x= 1/4+i(sqrt(7))/4 ,x= 1/4-i(sqrt(7))/4

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x^{2} - 0.5 x + 0.5 = 0

x = \frac{1}{4} + i \frac{7}{4}, x = \frac{1}{4} - i \frac{7}{4}

Solution steps

x^{2} - 0.5 x + 0.5 = 0

Multiply both sides by

10

10 x^{2} - 5 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 10 \cdot 5}{2 \cdot 10}

Simplify

(- 5)^{2} - 4 \cdot 10 \cdot 5 : 57 i

x_{1, 2} = \frac{- ( - 5 ) \pm 5 7 i}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 5 7 i}{2 \cdot 10}, x_{2} = \frac{- ( - 5 ) - 5 7 i}{2 \cdot 10}

x = \frac{- ( - 5 ) + 5 7 i}{2 \cdot 10} : \frac{1}{4} + i \frac{7}{4}

x = \frac{- ( - 5 ) - 5 7 i}{2 \cdot 10} : \frac{1}{4} - i \frac{7}{4}

The solutions to the quadratic equation are:

x = \frac{1}{4} + i \frac{7}{4}, x = \frac{1}{4} - i \frac{7}{4}

0 = - x^{2} + 12 x

x^{2} = 6 x - 117

y, x^{2} + y^{2} + 18 y + 81 = 18 x + 2 x y

- 4 x^{2} - 7 x + 36 = 0

4 x^{2} + 23 x = - 28

What are the solutions to the equation x^2-0.5x+0.5=0 ?
The solutions to the equation x^2-0.5x+0.5=0 are x= 1/4+i(sqrt(7))/4 ,x= 1/4-i(sqrt(7))/4
Find the zeros of x^2-0.5x+0.5=0
The zeros of x^2-0.5x+0.5=0 are x= 1/4+i(sqrt(7))/4 ,x= 1/4-i(sqrt(7))/4