What are the solutions to the equation 2x^2+3x+0.5=0 ?

The solutions to the equation 2x^2+3x+0.5=0 are x=(-3+sqrt(5))/4 ,x=-(3+sqrt(5))/4

Find the zeros of 2x^2+3x+0.5=0

The zeros of 2x^2+3x+0.5=0 are x=(-3+sqrt(5))/4 ,x=-(3+sqrt(5))/4

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2 x^{2} + 3 x + 0.5 = 0

x = \frac{- 3 + 5}{4}, x = - \frac{3 + 5}{4}

Decimal Notation

x = - 0.19098 \dots, x = - 1.30901 \dots

Solution steps

2 x^{2} + 3 x + 0.5 = 0

Multiply both sides by

10

20 x^{2} + 30 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 30 \pm 3 0 ^{2} - 4 \cdot 20 \cdot 5}{2 \cdot 20}

3 0^{2} - 4 \cdot 20 \cdot 5 = 105

x_{1, 2} = \frac{- 30 \pm 10 5}{2 \cdot 20}

Separate the solutions

x_{1} = \frac{- 30 + 10 5}{2 \cdot 20}, x_{2} = \frac{- 30 - 10 5}{2 \cdot 20}

x = \frac{- 30 + 10 5}{2 \cdot 20} : \frac{- 3 + 5}{4}

x = \frac{- 30 - 10 5}{2 \cdot 20} : - \frac{3 + 5}{4}

The solutions to the quadratic equation are:

x = \frac{- 3 + 5}{4}, x = - \frac{3 + 5}{4}

2 (x - 7)^{2} - 31 = 11

0 = 50 + 20 \cdot t - 4.9 \cdot t^{2}

(x + 1)^{2} = (2 x - 3)^{2}

- \frac{1}{2} (x - 7)^{2} = 96

\frac{4}{7} x^{2} = 0

What are the solutions to the equation 2x^2+3x+0.5=0 ?
The solutions to the equation 2x^2+3x+0.5=0 are x=(-3+sqrt(5))/4 ,x=-(3+sqrt(5))/4
Find the zeros of 2x^2+3x+0.5=0
The zeros of 2x^2+3x+0.5=0 are x=(-3+sqrt(5))/4 ,x=-(3+sqrt(5))/4