What are the solutions to the equation (x+1)^2=-6 ?

The solutions to the equation (x+1)^2=-6 are x=sqrt(6)i-1,x=-sqrt(6)i-1

Find the zeros of (x+1)^2=-6

The zeros of (x+1)^2=-6 are x=sqrt(6)i-1,x=-sqrt(6)i-1

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(x + 1)^{2} = - 6

x = 6 i - 1, x = - 6 i - 1

Solution steps

(x + 1)^{2} = - 6

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 1 = - 6 : x = 6 i - 1

Solve

x + 1 = - - 6 : x = - 6 i - 1

The solutions to the quadratic equation are:

x = 6 i - 1, x = - 6 i - 1

5 x^{2} - 5 x - 169 = 2 x^{2} + x + 5

(x + 3.5)^{2} - 0.25 = 0

0 = - \frac{1}{16} x^{2} + 4 x + 3

4 t^{2} + 12 t - 3 = 5 t

x^{2} - 10 x = - 14

What are the solutions to the equation (x+1)^2=-6 ?
The solutions to the equation (x+1)^2=-6 are x=sqrt(6)i-1,x=-sqrt(6)i-1
Find the zeros of (x+1)^2=-6
The zeros of (x+1)^2=-6 are x=sqrt(6)i-1,x=-sqrt(6)i-1