What are the solutions to the equation roots x^2+6x+3 ?

The solutions to the equation roots x^2+6x+3 are x=-3+sqrt(6),x=-3-sqrt(6)

Find the zeros of roots x^2+6x+3

The zeros of roots x^2+6x+3 are x=-3+sqrt(6),x=-3-sqrt(6)

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roots

x^{2} + 6 x + 3

x = - 3 + 6, x = - 3 - 6

Solution steps

x^{2} + 6 x + 3

The roots are the intercepts with the x-axis

(y = 0)

x^{2} + 6 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 3}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 3 = 26

x_{1, 2} = \frac{- 6 \pm 2 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 2 6}{2 \cdot 1}, x_{2} = \frac{- 6 - 2 6}{2 \cdot 1}

x = \frac{- 6 + 2 6}{2 \cdot 1} : - 3 + 6

x = \frac{- 6 - 2 6}{2 \cdot 1} : - 3 - 6

The solutions to the quadratic equation are:

x = - 3 + 6, x = - 3 - 6

x^{2} + 6 x + 5

2 x^{2} - 27 = 0

9 x^{2} - 30 x = 0

y^{2} = - 81

6 r^{2} - r - 1 = 0

What are the solutions to the equation roots x^2+6x+3 ?
The solutions to the equation roots x^2+6x+3 are x=-3+sqrt(6),x=-3-sqrt(6)
Find the zeros of roots x^2+6x+3
The zeros of roots x^2+6x+3 are x=-3+sqrt(6),x=-3-sqrt(6)