What are the solutions to the equation u(u+6)=3 ?

The solutions to the equation u(u+6)=3 are u=-3+2sqrt(3),u=-3-2sqrt(3)

Find the zeros of u(u+6)=3

The zeros of u(u+6)=3 are u=-3+2sqrt(3),u=-3-2sqrt(3)

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u (u + 6) = 3

u = - 3 + 23, u = - 3 - 23

Decimal Notation

u = 0.46410 \dots, u = - 6.46410 \dots

Solution steps

u (u + 6) = 3

Expand

u (u + 6) : u^{2} + 6 u

u^{2} + 6 u = 3

Move

3

to the left side

u^{2} + 6 u - 3 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 3 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 3) = 43

u_{1, 2} = \frac{- 6 \pm 4 3}{2 \cdot 1}

Separate the solutions

u_{1} = \frac{- 6 + 4 3}{2 \cdot 1}, u_{2} = \frac{- 6 - 4 3}{2 \cdot 1}

u = \frac{- 6 + 4 3}{2 \cdot 1} : - 3 + 23

u = \frac{- 6 - 4 3}{2 \cdot 1} : - 3 - 23

The solutions to the quadratic equation are:

u = - 3 + 23, u = - 3 - 23

48 = 3 (x - 1)^{2}

x^{2} - 18 = - 7 x

x^{2} - 36 = 12 x

- 2 x^{2} - 5 = 3 x^{2} - 10 x

2 x^{2} - 18 x + 5 = 0

What are the solutions to the equation u(u+6)=3 ?
The solutions to the equation u(u+6)=3 are u=-3+2sqrt(3),u=-3-2sqrt(3)
Find the zeros of u(u+6)=3
The zeros of u(u+6)=3 are u=-3+2sqrt(3),u=-3-2sqrt(3)