What are the solutions to the equation 4x^2+268=-72x ?

The solutions to the equation 4x^2+268=-72x are x=-9+sqrt(14),x=-9-sqrt(14)

Find the zeros of 4x^2+268=-72x

The zeros of 4x^2+268=-72x are x=-9+sqrt(14),x=-9-sqrt(14)

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4 x^{2} + 268 = - 72 x

x = - 9 + 14, x = - 9 - 14

Decimal Notation

x = - 5.25834 \dots, x = - 12.74165 \dots

Solution steps

4 x^{2} + 268 = - 72 x

Move

72 x

to the left side

4 x^{2} + 268 + 72 x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} + 72 x + 268 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 72 \pm 7 2 ^{2} - 4 \cdot 4 \cdot 268}{2 \cdot 4}

7 2^{2} - 4 \cdot 4 \cdot 268 = 814

x_{1, 2} = \frac{- 72 \pm 8 14}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 72 + 8 14}{2 \cdot 4}, x_{2} = \frac{- 72 - 8 14}{2 \cdot 4}

x = \frac{- 72 + 8 14}{2 \cdot 4} : - 9 + 14

x = \frac{- 72 - 8 14}{2 \cdot 4} : - 9 - 14

The solutions to the quadratic equation are:

x = - 9 + 14, x = - 9 - 14

a \cdot a + a = 240

x^{2} - 14 x - 20 = 0

2 x^{2} - 3 = 69

7 x^{2} - 4 x - 20 = 0

x^{2} - 3 x - 54 = 0

What are the solutions to the equation 4x^2+268=-72x ?
The solutions to the equation 4x^2+268=-72x are x=-9+sqrt(14),x=-9-sqrt(14)
Find the zeros of 4x^2+268=-72x
The zeros of 4x^2+268=-72x are x=-9+sqrt(14),x=-9-sqrt(14)