What are the solutions to the equation 2x^2+15x=x^2+9x ?

The solutions to the equation 2x^2+15x=x^2+9x are x=0,x=-6

Find the zeros of 2x^2+15x=x^2+9x

The zeros of 2x^2+15x=x^2+9x are x=0,x=-6

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2 x^{2} + 15 x = x^{2} + 9 x

x = 0, x = - 6

Solution steps

2 x^{2} + 15 x = x^{2} + 9 x

Move

9 x

to the left side

2 x^{2} + 6 x = x^{2}

Move

x^{2}

to the left side

x^{2} + 6 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot 0 = 6

x_{1, 2} = \frac{- 6 \pm 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 6}{2 \cdot 1}, x_{2} = \frac{- 6 - 6}{2 \cdot 1}

x = \frac{- 6 + 6}{2 \cdot 1} : 0

x = \frac{- 6 - 6}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

x = 0, x = - 6

3 x^{2} - 4 x - 1

9 x^{2} - 1 = 35

2 x^{2} - 8 = - 17

3 u^{2} + 6 = - 11 u

k^{2} + 10 k + 15 = 0

What are the solutions to the equation 2x^2+15x=x^2+9x ?
The solutions to the equation 2x^2+15x=x^2+9x are x=0,x=-6
Find the zeros of 2x^2+15x=x^2+9x
The zeros of 2x^2+15x=x^2+9x are x=0,x=-6