What are the solutions to the equation 5a^2-7a-10=0 ?

The solutions to the equation 5a^2-7a-10=0 are a=(7+sqrt(249))/(10),a=(7-sqrt(249))/(10)

Find the zeros of 5a^2-7a-10=0

The zeros of 5a^2-7a-10=0 are a=(7+sqrt(249))/(10),a=(7-sqrt(249))/(10)

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5 a^{2} - 7 a - 10 = 0

a = \frac{7 + 249}{10}, a = \frac{7 - 249}{10}

Decimal Notation

a = 2.27797 \dots, a = - 0.87797 \dots

Solution steps

5 a^{2} - 7 a - 10 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 5 ( - 10 )}{2 \cdot 5}

(- 7)^{2} - 4 \cdot 5 (- 10) = 249

a_{1, 2} = \frac{- ( - 7 ) \pm 249}{2 \cdot 5}

Separate the solutions

a_{1} = \frac{- ( - 7 ) + 249}{2 \cdot 5}, a_{2} = \frac{- ( - 7 ) - 249}{2 \cdot 5}

a = \frac{- ( - 7 ) + 249}{2 \cdot 5} : \frac{7 + 249}{10}

a = \frac{- ( - 7 ) - 249}{2 \cdot 5} : \frac{7 - 249}{10}

The solutions to the quadratic equation are:

a = \frac{7 + 249}{10}, a = \frac{7 - 249}{10}

2 x^{2} + 24 x + 32 = 0

x^{2} + 15 x + 54 = 0

x^{2} = 6 x + 1

r^{2} - 9

x^{2} - 2 x + 1 = 144

What are the solutions to the equation 5a^2-7a-10=0 ?
The solutions to the equation 5a^2-7a-10=0 are a=(7+sqrt(249))/(10),a=(7-sqrt(249))/(10)
Find the zeros of 5a^2-7a-10=0
The zeros of 5a^2-7a-10=0 are a=(7+sqrt(249))/(10),a=(7-sqrt(249))/(10)