What are the solutions to the equation 5=s^2-5s ?

The solutions to the equation 5=s^2-5s are s=(5+3sqrt(5))/2 ,s=(5-3sqrt(5))/2

Find the zeros of 5=s^2-5s

The zeros of 5=s^2-5s are s=(5+3sqrt(5))/2 ,s=(5-3sqrt(5))/2

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5 = s^{2} - 5 s

s = \frac{5 + 3 5}{2}, s = \frac{5 - 3 5}{2}

Decimal

s = 5.85410 \dots, s = - 0.85410 \dots

Solution steps

5 = s^{2} - 5 s

Switch sides

s^{2} - 5 s = 5

Move

5

to the left side

s^{2} - 5 s - 5 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 5 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 5) = 35

s_{1, 2} = \frac{- ( - 5 ) \pm 3 5}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- ( - 5 ) + 3 5}{2 \cdot 1}, s_{2} = \frac{- ( - 5 ) - 3 5}{2 \cdot 1}

s = \frac{- ( - 5 ) + 3 5}{2 \cdot 1} : \frac{5 + 3 5}{2}

s = \frac{- ( - 5 ) - 3 5}{2 \cdot 1} : \frac{5 - 3 5}{2}

The solutions to the quadratic equation are:

s = \frac{5 + 3 5}{2}, s = \frac{5 - 3 5}{2}

3 x^{2} + 5 x - 4 = x^{2} - 2 x

x^{2} + 6 x - 72 = 0

2 x^{2} + 15 = - 35

(4 x) (x - 5) = 0

2 x^{2} + 18 = 3 x - 13

What are the solutions to the equation 5=s^2-5s ?
The solutions to the equation 5=s^2-5s are s=(5+3sqrt(5))/2 ,s=(5-3sqrt(5))/2
Find the zeros of 5=s^2-5s
The zeros of 5=s^2-5s are s=(5+3sqrt(5))/2 ,s=(5-3sqrt(5))/2