What are the solutions to the equation x^2+22x+20=3x^2 ?

The solutions to the equation x^2+22x+20=3x^2 are x=-(-11+sqrt(161))/2 ,x=(11+sqrt(161))/2

Find the zeros of x^2+22x+20=3x^2

The zeros of x^2+22x+20=3x^2 are x=-(-11+sqrt(161))/2 ,x=(11+sqrt(161))/2

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x^{2} + 22 x + 20 = 3 x^{2}

x = - \frac{- 11 + 161}{2}, x = \frac{11 + 161}{2}

Decimal Notation

x = - 0.84428 \dots, x = 11.84428 \dots

Solution steps

x^{2} + 22 x + 20 = 3 x^{2}

Move

3 x^{2}

to the left side

- 2 x^{2} + 22 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 22 \pm 2 2 ^{2} - 4 ( - 2 ) \cdot 20}{2 ( - 2 )}

2 2^{2} - 4 (- 2) \cdot 20 = 2161

x_{1, 2} = \frac{- 22 \pm 2 161}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 22 + 2 161}{2 ( - 2 )}, x_{2} = \frac{- 22 - 2 161}{2 ( - 2 )}

x = \frac{- 22 + 2 161}{2 ( - 2 )} : - \frac{- 11 + 161}{2}

x = \frac{- 22 - 2 161}{2 ( - 2 )} : \frac{11 + 161}{2}

The solutions to the quadratic equation are:

x = - \frac{- 11 + 161}{2}, x = \frac{11 + 161}{2}

x^{2} + 12 x + 63 = 0

x^{2} - 2 x - 4 = - 2 x

x^{2} - 12 x = 0

3 x - 2 = x^{2} + 5 x - 2

x (x + 4) = 154

What are the solutions to the equation x^2+22x+20=3x^2 ?
The solutions to the equation x^2+22x+20=3x^2 are x=-(-11+sqrt(161))/2 ,x=(11+sqrt(161))/2
Find the zeros of x^2+22x+20=3x^2
The zeros of x^2+22x+20=3x^2 are x=-(-11+sqrt(161))/2 ,x=(11+sqrt(161))/2