What are the solutions to the equation x^2-7x=-2-5x ?

The solutions to the equation x^2-7x=-2-5x are x=1+i,x=1-i

Find the zeros of x^2-7x=-2-5x

The zeros of x^2-7x=-2-5x are x=1+i,x=1-i

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x^{2} - 7 x = - 2 - 5 x

x = 1 + i, x = 1 - i

Solution steps

x^{2} - 7 x = - 2 - 5 x

Move

5 x

to the left side

x^{2} - 2 x = - 2

Move

2

to the left side

x^{2} - 2 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

Simplify

(- 2)^{2} - 4 \cdot 1 \cdot 2 : 2 i

x_{1, 2} = \frac{- ( - 2 ) \pm 2 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 2 i}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 2 i}{2 \cdot 1}

x = \frac{- ( - 2 ) + 2 i}{2 \cdot 1} : 1 + i

x = \frac{- ( - 2 ) - 2 i}{2 \cdot 1} : 1 - i

The solutions to the quadratic equation are:

x = 1 + i, x = 1 - i

y, x^{2} + y^{2} - 6 x - 8 y + 100 = 0

x^{2} = π

\frac{8 x ^{2} - 18 - 24 x - 3 + x}{8} = x - x^{2}

x^{2} - 144 = 0

\frac{1}{4} x^{2} + x + 1 = 0

What are the solutions to the equation x^2-7x=-2-5x ?
The solutions to the equation x^2-7x=-2-5x are x=1+i,x=1-i
Find the zeros of x^2-7x=-2-5x
The zeros of x^2-7x=-2-5x are x=1+i,x=1-i