What are the solutions to the equation factor 7v^2-42=-35v ?

The solutions to the equation factor 7v^2-42=-35v are v=1,v=-6

Find the zeros of factor 7v^2-42=-35v

The zeros of factor 7v^2-42=-35v are v=1,v=-6

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7 v^{2} - 42 = - 35 v

v = 1, v = - 6

Solution steps

7 v^{2} - 42 = - 35 v

Move

35 v

to the left side

7 v^{2} - 42 + 35 v = 0

Write in the standard form

a x^{2} + b x + c = 0

7 v^{2} + 35 v - 42 = 0

Factor

7 v^{2} + 35 v - 42 : 7 (v - 1) (v + 6)

7 (v - 1) (v + 6) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

v - 1 = 0 or v + 6 = 0

Solve

v - 1 = 0 : v = 1

Solve

v + 6 = 0 : v = - 6

The solutions to the quadratic equation are:

v = 1, v = - 6

3 x^{2} - 7 x - 6 = 0

2 x^{2} - x - 29 = 15

3 x^{2} - 75 = 0

4 x^{2} + 22 x = 0

x^{2} = 16

What are the solutions to the equation factor 7v^2-42=-35v ?
The solutions to the equation factor 7v^2-42=-35v are v=1,v=-6
Find the zeros of factor 7v^2-42=-35v
The zeros of factor 7v^2-42=-35v are v=1,v=-6