What are the solutions to the equation 3(5x-10)^2=27 ?

The solutions to the equation 3(5x-10)^2=27 are x= 13/5 ,x= 7/5

Find the zeros of 3(5x-10)^2=27

The zeros of 3(5x-10)^2=27 are x= 13/5 ,x= 7/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

3 (5 x - 10)^{2} = 27

x = \frac{13}{5}, x = \frac{7}{5}

Decimal Notation

x = 2.6, x = 1.4

Solution steps

3 (5 x - 10)^{2} = 27

Divide both sides by

3

(5 x - 10)^{2} = 9

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

5 x - 10 = 9 : x = \frac{13}{5}

Solve

5 x - 10 = - 9 : x = \frac{7}{5}

The solutions to the quadratic equation are:

x = \frac{13}{5}, x = \frac{7}{5}

8 x^{2} + 2 x - 6 = 0

(x - 11) (5 x + 1) = 0

x^{2} + 2 x + 15

4.5 \times 1 0^{- 4} = \frac{x ^{2}}{0.03}

x^{2} - 15 = - 271

What are the solutions to the equation 3(5x-10)^2=27 ?
The solutions to the equation 3(5x-10)^2=27 are x= 13/5 ,x= 7/5
Find the zeros of 3(5x-10)^2=27
The zeros of 3(5x-10)^2=27 are x= 13/5 ,x= 7/5