What are the solutions to the equation (8+v)(4v-5)=0 ?

The solutions to the equation (8+v)(4v-5)=0 are v=-8,v= 5/4

Find the zeros of (8+v)(4v-5)=0

The zeros of (8+v)(4v-5)=0 are v=-8,v= 5/4

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(8 + v) (4 v - 5) = 0

v = - 8, v = \frac{5}{4}

Decimal Notation

v = - 8, v = 1.25

Solution steps

(8 + v) (4 v - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

8 + v = 0 or 4 v - 5 = 0

Solve

8 + v = 0 : v = - 8

Solve

4 v - 5 = 0 : v = \frac{5}{4}

The solutions to the quadratic equation are:

v = - 8, v = \frac{5}{4}

14 h - 40 = 6 h^{2}

4 x^{2} - 29 x - 20 = 0

(2 x - 5) (x + 2) - (x + 2) (3 x - 1) = 0

3 t^{2} - 40 t + 128 = 0

4 x^{2} + 36 x + 27 = 7 x^{2} + 54 x + 51

What are the solutions to the equation (8+v)(4v-5)=0 ?
The solutions to the equation (8+v)(4v-5)=0 are v=-8,v= 5/4
Find the zeros of (8+v)(4v-5)=0
The zeros of (8+v)(4v-5)=0 are v=-8,v= 5/4