What are the solutions to the equation x^2+4\times (-21)=0 ?

The solutions to the equation x^2+4\times (-21)=0 are x=2sqrt(21),x=-2sqrt(21)

Find the zeros of x^2+4\times (-21)=0

The zeros of x^2+4\times (-21)=0 are x=2sqrt(21),x=-2sqrt(21)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 4 \cdot (- 21) = 0

x = 221, x = - 221

Decimal Notation

x = 9.16515 \dots, x = - 9.16515 \dots

Solution steps

x^{2} + 4 (- 21) = 0

Expand

x^{2} + 4 (- 21) : x^{2} - 84

x^{2} - 84 = 0

Move

84

to the right side

x^{2} = 84

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 84, x = - 84

84 = 221

- 84 = - 221

x = 221, x = - 221

4 y^{2} = - 4 y - 1

76 = 3 m^{2} + 10

b^{2} - \frac{1}{8} = (\frac{1}{4}) b

2 x - 3 = x^{2} - 2 x + 1

- x^{2} - 8

What are the solutions to the equation x^2+4\times (-21)=0 ?
The solutions to the equation x^2+4\times (-21)=0 are x=2sqrt(21),x=-2sqrt(21)
Find the zeros of x^2+4\times (-21)=0
The zeros of x^2+4\times (-21)=0 are x=2sqrt(21),x=-2sqrt(21)