What are the solutions to the equation factor 3x^2-7=7x-1 ?

The solutions to the equation factor 3x^2-7=7x-1 are x=-2/3 ,x=3

Find the zeros of factor 3x^2-7=7x-1

The zeros of factor 3x^2-7=7x-1 are x=-2/3 ,x=3

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3 x^{2} - 7 = 7 x - 1

x = - \frac{2}{3}, x = 3

Decimal

x = - 0.66666 \dots, x = 3

Solution steps

3 x^{2} - 7 = 7 x - 1

Move

1

to the left side

3 x^{2} - 6 = 7 x

Move

7 x

to the left side

3 x^{2} - 6 - 7 x = 0

Write in the standard form

a x^{2} + b x + c = 0

3 x^{2} - 7 x - 6 = 0

Factor

3 x^{2} - 7 x - 6 : (3 x + 2) (x - 3)

(3 x + 2) (x - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x + 2 = 0 or x - 3 = 0

Solve

3 x + 2 = 0 : x = - \frac{2}{3}

Solve

x - 3 = 0 : x = 3

The solutions to the quadratic equation are:

x = - \frac{2}{3}, x = 3

x^{2} + 16 x + 51 = 0

x^{2} + 9 = - 40

y, x^{2} y^{2} - 2 x y^{2} + y^{2} - x = 0

5 t^{2} + 10 t - 40 = 0

- 33 x^{2} + 14 x + 5 = 0

What are the solutions to the equation factor 3x^2-7=7x-1 ?
The solutions to the equation factor 3x^2-7=7x-1 are x=-2/3 ,x=3
Find the zeros of factor 3x^2-7=7x-1
The zeros of factor 3x^2-7=7x-1 are x=-2/3 ,x=3