What are the solutions to the equation k(k-3)=0 ?

The solutions to the equation k(k-3)=0 are k=0,k=3

Find the zeros of k(k-3)=0

The zeros of k(k-3)=0 are k=0,k=3

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k (k - 3) = 0

k = 0, k = 3

Solution steps

k (k - 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

k = 0 or k - 3 = 0

Solve

k - 3 = 0 : k = 3

The solutions to the quadratic equation are:

k = 0, k = 3

x^{2} + 0 x + 14 = 0

(x + 1)^{2} + 5 = 0

x^{2} + 16 x = 42

- 2 x^{2} - 12 x - 14 = 0

y, x^{2} + y^{2} + 4 x + 2 x = - 16

What are the solutions to the equation k(k-3)=0 ?
The solutions to the equation k(k-3)=0 are k=0,k=3
Find the zeros of k(k-3)=0
The zeros of k(k-3)=0 are k=0,k=3