What is the answer to solvefor f,f(1-x)=x^2-2x ?

The answer to solvefor f,f(1-x)=x^2-2x is f=(x^2-2x)/(1-x);\quad x\ne 1

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solvefor f,f(1-x)=x^2-2x

solve for

f, f (1 - x) = x^{2} - 2 x

f = \frac{x ^{2} - 2 x}{1 - x}; x \neq = 1

Solution steps

f (1 - x) = x^{2} - 2 x

Divide both sides by

1 - x; x \neq = 1

f = \frac{x ^{2} - 2 x}{1 - x}; x \neq = 1

4 x^{2} + 8 x + 3 = a (x + b)^{2} + e

2 x^{2} = - 6 + 8 x

x^{2} + 2 x - 3 = 0

6 x^{2} - 20 = 0

x, x^{2} + 10 x + 21 = 0

What is the answer to solvefor f,f(1-x)=x^2-2x ?
The answer to solvefor f,f(1-x)=x^2-2x is f=(x^2-2x)/(1-x);\quad x\ne 1