What are the solutions to the equation 3x^2-(x+3)^2=x^2-17 ?

The solutions to the equation 3x^2-(x+3)^2=x^2-17 are x=4,x=2

Find the zeros of 3x^2-(x+3)^2=x^2-17

The zeros of 3x^2-(x+3)^2=x^2-17 are x=4,x=2

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3 x^{2} - (x + 3)^{2} = x^{2} - 17

x = 4, x = 2

Solution steps

3 x^{2} - (x + 3)^{2} = x^{2} - 17

Expand

3 x^{2} - (x + 3)^{2} : 2 x^{2} - 6 x - 9

2 x^{2} - 6 x - 9 = x^{2} - 17

Move

17

to the left side

2 x^{2} - 6 x + 8 = x^{2}

Move

x^{2}

to the left side

x^{2} - 6 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 8 = 2

x_{1, 2} = \frac{- ( - 6 ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 2}{2 \cdot 1}

x = \frac{- ( - 6 ) + 2}{2 \cdot 1} : 4

x = \frac{- ( - 6 ) - 2}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

x = 4, x = 2

y^{2} + 11 = 6

x^{2} - 15 x = 0

x^{2} - 16 x + 56 = 0

6 x^{2} - 16 x = 0

9 x^{2} + 14 x - 15 = 0

What are the solutions to the equation 3x^2-(x+3)^2=x^2-17 ?
The solutions to the equation 3x^2-(x+3)^2=x^2-17 are x=4,x=2
Find the zeros of 3x^2-(x+3)^2=x^2-17
The zeros of 3x^2-(x+3)^2=x^2-17 are x=4,x=2